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-# CLooG example file #3.
-# Please read the first example which is fully documented to understand the
-# different parts of this input file.
-#
-################################################################################
-# The problem here is to generate the scanning code for the integral points #
-# inside two different 2-dimensional polyhedra (geometrically two rectangles). #
-# | #
-# j^ | #
-# | (P1)i>=2 | for (i=2;i<=p-1;i++) #
-# Context: | | (P2)i>=m | | for (j=2;j<=n;j++) #
-# m>n>p>2 | | | (P1)i<=n | | | S1 ; #
-# | | | | (P2)i<=p | #
-# P1 System: | | | | | | for (i=p;i<=n;i++) #
-# 2<=i<=n m-+-+-@@@@@--(P2)j<=p | | for (j=2;j<=p-1;j++) #
-# 2<=j<=n | | @@@@@ ==> | | S1 ; #
-# n-+-**###@@--(P1)j<=n | | for (j=p;j<=n;j++) #
-# P2 System: | **###@@ | | | S1 ; #
-# p<=i<=m p-+-**###@@--(P2)j>=m | | | S2 ; #
-# p<=j<=m | ***** | | | for (j=n+1;j<=m;j++) #
-# 2-+-*****-+--(P1)j>=2 | | | S2 ; #
-# *:P1 alone | | | | | | #
-# @:P2 alone 0-+-+-+-+-+-->i | for (i=n+1;i<=m;i++) #
-# #:P1 and P2 | | | | | | | for (j=p;j<=m;j++) #
-# 0 2 p n m | | | S2 ; #
-# | #
-################################################################################
-
-# 1. Language: C
-c
-
-# 2. Parameters {m,n,p | m>n>p>2}
-3 5 # 3 rows and 5 columns
-# m n p 1
-1 0 0 1 -3 # p>=3 (i.e. p>2)
-1 0 1 -1 -1 # n>=p+1 (i.e. n>p)
-1 1 -1 0 -1 # m>=n+1 (i.e. m>n)
-
-# 3. We set manually the parameter name: m, n and p
-1
-m n p
-
-# 4. Number of polyhedra:
-2
-
-# 5. The polyhedron description:
-# - the first one
-1
-# {i, j | 2<=i<=n 2<=j<=n}
-4 7 # 4 rows, 7 columns
-# i j m n p 1
-1 1 0 0 0 0 -2 # i>=2
-1 -1 0 0 1 0 0 # i<=n
-1 0 1 0 0 0 -2 # j>=2
-1 0 -1 0 1 0 0 # j<=n
-0 0 0 # 3 zeroes !
-
-# - the second one
-1
-# {j, j | p<=i<=m p<=j<=m}
-4 7 # 4 rows, 7 columns
-# i j m n p 1
-1 1 0 0 0 -1 0 # i>=p
-1 -1 0 1 0 0 0 # i<=m
-1 0 1 0 0 -1 0 # j>=p
-1 0 -1 1 0 0 0 # j<=m
-0 0 0 # 3 zeroes !
-
-# 6. We let CLooG choose the iterator names
-0
-
-# 7. Let CLoog scan the polyhedra in the way it wants.
-0