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authorjulie <julielangou@users.noreply.github.com>2011-04-02 11:08:56 +0000
committerjulie <julielangou@users.noreply.github.com>2011-04-02 11:08:56 +0000
commitf2953573ede24d7f8c01fdb18de48f65f00a9943 (patch)
tree53172aa9083b9aa1abe2d6c130f7c173d8d8725b /SRC/ctrsen.f
parent53b71f5605f83d116ab6bcf477bfb6d2ca757de1 (diff)
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First pass to homgenize notation for transpose (**T) and conjugate transpose (**H)
Corresponds to bug0024
Diffstat (limited to 'SRC/ctrsen.f')
-rw-r--r--SRC/ctrsen.f10
1 files changed, 5 insertions, 5 deletions
diff --git a/SRC/ctrsen.f b/SRC/ctrsen.f
index 2b35ef3c..a5eb9d70 100644
--- a/SRC/ctrsen.f
+++ b/SRC/ctrsen.f
@@ -119,16 +119,16 @@
* transformation Z to move them to the top left corner of T. In other
* words, the selected eigenvalues are the eigenvalues of T11 in:
*
-* Z'*T*Z = ( T11 T12 ) n1
+* Z**H * T * Z = ( T11 T12 ) n1
* ( 0 T22 ) n2
* n1 n2
*
-* where N = n1+n2 and Z' means the conjugate transpose of Z. The first
+* where N = n1+n2. The first
* n1 columns of Z span the specified invariant subspace of T.
*
* If T has been obtained from the Schur factorization of a matrix
-* A = Q*T*Q', then the reordered Schur factorization of A is given by
-* A = (Q*Z)*(Z'*T*Z)*(Q*Z)', and the first n1 columns of Q*Z span the
+* A = Q*T*Q**H, then the reordered Schur factorization of A is given by
+* A = (Q*Z)*(Z**H*T*Z)*(Q*Z)**H, and the first n1 columns of Q*Z span the
* corresponding invariant subspace of A.
*
* The reciprocal condition number of the average of the eigenvalues of
@@ -331,7 +331,7 @@
$ IERR )
ELSE
*
-* Solve T11'*R - R*T22' = scale*X.
+* Solve T11**H*R - R*T22**H = scale*X.
*
CALL CTRSYL( 'C', 'C', -1, N1, N2, T, LDT,
$ T( N1+1, N1+1 ), LDT, WORK, N1, SCALE,