#!/bin/sh
i=128
a="sed"
echo="`which echo`"
while [ $i -lt 256 ]; do
	oct="`printf %03o $i`"
	# dash's internal echo doesn't know -e
	char="`"$echo" -e \\\\$oct`"
	a="$a -e 's/$char/\\\\\\\\$oct/g'"
	i=`expr $i + 1`
done
# bash and dash differ here: bash creates double backslashes, dash single
echo "$a"|sed 's/\\\\\\\\/\\\\/g'