buildman: Don't show a stacktrace on Ctrl-C

When Ctrl-C is pressed, just exited quietly. There is no sense in displaying
a stack trace since buildman will always be in the same place: waiting for
threads to complete building all the jobs on the queue.

Signed-off-by: Simon Glass <sjg@chromium.org>

1 files changed, 7 insertions, 0 deletions

diff --git a/tools/buildman/builder.py b/tools/buildman/builder.py
index 5addbca44e..e27a28577c 100644
--- a/tools/buildman/builder.py
+++ b/tools/buildman/builder.py
@@ -12,6 +12,7 @@ import os
 import re
 import Queue
 import shutil
+import signal
 import string
 import sys
 import threading
@@ -282,11 +283,17 @@ class Builder:
         ignore_lines = ['(make.*Waiting for unfinished)', '(Segmentation fault)']
         self.re_make_err = re.compile('|'.join(ignore_lines))
 
+        # Handle existing graceful with SIGINT / Ctrl-C
+        signal.signal(signal.SIGINT, self.signal_handler)
+
     def __del__(self):
         """Get rid of all threads created by the builder"""
         for t in self.threads:
             del t
 
+    def signal_handler(self, signal, frame):
+        sys.exit(1)
+
     def SetDisplayOptions(self, show_errors=False, show_sizes=False,
                           show_detail=False, show_bloat=False,
                           list_error_boards=False, show_config=False):