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author | Tao Ma <tao.ma@oracle.com> | 2008-10-27 06:06:24 +0800 |
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committer | Mark Fasheh <mfasheh@suse.com> | 2008-11-10 09:51:47 -0800 |
commit | 80bcaf3469b8aefd316d4ceb27d9af7cfbb0b913 (patch) | |
tree | 250e38e24f88aeb5bd89b5f4fca3304207eec0f1 /fs/ocfs2 | |
parent | 4c1bbf1ba631d7db61ce3462349a3f5d14ae3009 (diff) | |
download | linux-3.10-80bcaf3469b8aefd316d4ceb27d9af7cfbb0b913.tar.gz linux-3.10-80bcaf3469b8aefd316d4ceb27d9af7cfbb0b913.tar.bz2 linux-3.10-80bcaf3469b8aefd316d4ceb27d9af7cfbb0b913.zip |
ocfs2/xattr: Proper hash collision handle in bucket division
In ocfs2/xattr, we must make sure the xattrs which have the same hash value
exist in the same bucket so that the search schema can work. But in the old
implementation, when we want to extend a bucket, we just move half number of
xattrs to the new bucket. This works in most cases, but if we are lucky
enough we will move 2 xattrs into 2 different buckets. This means that an
xattr from the previous bucket cannot be found anymore. This patch fix this
problem by finding the right position during extending the bucket and extend
an empty bucket if needed.
Signed-off-by: Tao Ma <tao.ma@oracle.com>
Cc: Joel Becker <joel.becker@oracle.com>
Signed-off-by: Mark Fasheh <mfasheh@suse.com>
Diffstat (limited to 'fs/ocfs2')
-rw-r--r-- | fs/ocfs2/xattr.c | 144 |
1 files changed, 115 insertions, 29 deletions
diff --git a/fs/ocfs2/xattr.c b/fs/ocfs2/xattr.c index a371c01942b..f3ea7efb48c 100644 --- a/fs/ocfs2/xattr.c +++ b/fs/ocfs2/xattr.c @@ -3110,25 +3110,73 @@ static int ocfs2_read_xattr_bucket(struct inode *inode, } /* - * Move half num of the xattrs in old bucket(blk) to new bucket(new_blk). + * Find the suitable pos when we divide a bucket into 2. + * We have to make sure the xattrs with the same hash value exist + * in the same bucket. + * + * If this ocfs2_xattr_header covers more than one hash value, find a + * place where the hash value changes. Try to find the most even split. + * The most common case is that all entries have different hash values, + * and the first check we make will find a place to split. + */ +static int ocfs2_xattr_find_divide_pos(struct ocfs2_xattr_header *xh) +{ + struct ocfs2_xattr_entry *entries = xh->xh_entries; + int count = le16_to_cpu(xh->xh_count); + int delta, middle = count / 2; + + /* + * We start at the middle. Each step gets farther away in both + * directions. We therefore hit the change in hash value + * nearest to the middle. Note that this loop does not execute for + * count < 2. + */ + for (delta = 0; delta < middle; delta++) { + /* Let's check delta earlier than middle */ + if (cmp_xe(&entries[middle - delta - 1], + &entries[middle - delta])) + return middle - delta; + + /* For even counts, don't walk off the end */ + if ((middle + delta + 1) == count) + continue; + + /* Now try delta past middle */ + if (cmp_xe(&entries[middle + delta], + &entries[middle + delta + 1])) + return middle + delta + 1; + } + + /* Every entry had the same hash */ + return count; +} + +/* + * Move some xattrs in old bucket(blk) to new bucket(new_blk). * first_hash will record the 1st hash of the new bucket. + * + * Normally half of the xattrs will be moved. But we have to make + * sure that the xattrs with the same hash value are stored in the + * same bucket. If all the xattrs in this bucket have the same hash + * value, the new bucket will be initialized as an empty one and the + * first_hash will be initialized as (hash_value+1). */ -static int ocfs2_half_xattr_bucket(struct inode *inode, - handle_t *handle, - u64 blk, - u64 new_blk, - u32 *first_hash, - int new_bucket_head) +static int ocfs2_divide_xattr_bucket(struct inode *inode, + handle_t *handle, + u64 blk, + u64 new_blk, + u32 *first_hash, + int new_bucket_head) { int ret, i; - u16 count, start, len, name_value_len, xe_len, name_offset; + int count, start, len, name_value_len = 0, xe_len, name_offset = 0; u16 blk_per_bucket = ocfs2_blocks_per_xattr_bucket(inode->i_sb); struct buffer_head **s_bhs, **t_bhs = NULL; struct ocfs2_xattr_header *xh; struct ocfs2_xattr_entry *xe; int blocksize = inode->i_sb->s_blocksize; - mlog(0, "move half of xattrs from bucket %llu to %llu\n", + mlog(0, "move some of xattrs from bucket %llu to %llu\n", blk, new_blk); s_bhs = kcalloc(blk_per_bucket, sizeof(struct buffer_head *), GFP_NOFS); @@ -3171,14 +3219,35 @@ static int ocfs2_half_xattr_bucket(struct inode *inode, } } + xh = (struct ocfs2_xattr_header *)s_bhs[0]->b_data; + count = le16_to_cpu(xh->xh_count); + start = ocfs2_xattr_find_divide_pos(xh); + + if (start == count) { + xe = &xh->xh_entries[start-1]; + + /* + * initialized a new empty bucket here. + * The hash value is set as one larger than + * that of the last entry in the previous bucket. + */ + for (i = 0; i < blk_per_bucket; i++) + memset(t_bhs[i]->b_data, 0, blocksize); + + xh = (struct ocfs2_xattr_header *)t_bhs[0]->b_data; + xh->xh_free_start = cpu_to_le16(blocksize); + xh->xh_entries[0].xe_name_hash = xe->xe_name_hash; + le32_add_cpu(&xh->xh_entries[0].xe_name_hash, 1); + + goto set_num_buckets; + } + /* copy the whole bucket to the new first. */ for (i = 0; i < blk_per_bucket; i++) memcpy(t_bhs[i]->b_data, s_bhs[i]->b_data, blocksize); /* update the new bucket. */ xh = (struct ocfs2_xattr_header *)t_bhs[0]->b_data; - count = le16_to_cpu(xh->xh_count); - start = count / 2; /* * Calculate the total name/value len and xh_free_start for @@ -3235,6 +3304,7 @@ static int ocfs2_half_xattr_bucket(struct inode *inode, xh->xh_free_start = xe->xe_name_offset; } +set_num_buckets: /* set xh->xh_num_buckets for the new xh. */ if (new_bucket_head) xh->xh_num_buckets = cpu_to_le16(1); @@ -3252,9 +3322,13 @@ static int ocfs2_half_xattr_bucket(struct inode *inode, *first_hash = le32_to_cpu(xh->xh_entries[0].xe_name_hash); /* - * Now only update the 1st block of the old bucket. - * Please note that the entry has been sorted already above. + * Now only update the 1st block of the old bucket. If we + * just added a new empty bucket, there is no need to modify + * it. */ + if (start == count) + goto out; + xh = (struct ocfs2_xattr_header *)s_bhs[0]->b_data; memset(&xh->xh_entries[start], 0, sizeof(struct ocfs2_xattr_entry) * (count - start)); @@ -3439,15 +3513,15 @@ out: } /* - * Move half of the xattrs in this cluster to the new cluster. + * Move some xattrs in this cluster to the new cluster. * This function should only be called when bucket size == cluster size. * Otherwise ocfs2_mv_xattr_bucket_cross_cluster should be used instead. */ -static int ocfs2_half_xattr_cluster(struct inode *inode, - handle_t *handle, - u64 prev_blk, - u64 new_blk, - u32 *first_hash) +static int ocfs2_divide_xattr_cluster(struct inode *inode, + handle_t *handle, + u64 prev_blk, + u64 new_blk, + u32 *first_hash) { u16 blk_per_bucket = ocfs2_blocks_per_xattr_bucket(inode->i_sb); int ret, credits = 2 * blk_per_bucket; @@ -3461,8 +3535,8 @@ static int ocfs2_half_xattr_cluster(struct inode *inode, } /* Move half of the xattr in start_blk to the next bucket. */ - return ocfs2_half_xattr_bucket(inode, handle, prev_blk, - new_blk, first_hash, 1); + return ocfs2_divide_xattr_bucket(inode, handle, prev_blk, + new_blk, first_hash, 1); } /* @@ -3524,9 +3598,9 @@ static int ocfs2_adjust_xattr_cross_cluster(struct inode *inode, last_blk, new_blk, v_start); else { - ret = ocfs2_half_xattr_cluster(inode, handle, - last_blk, new_blk, - v_start); + ret = ocfs2_divide_xattr_cluster(inode, handle, + last_blk, new_blk, + v_start); if ((*header_bh)->b_blocknr == last_blk && extend) *extend = 0; @@ -3743,8 +3817,8 @@ static int ocfs2_extend_xattr_bucket(struct inode *inode, } /* Move half of the xattr in start_blk to the next bucket. */ - ret = ocfs2_half_xattr_bucket(inode, handle, start_blk, - start_blk + blk_per_bucket, NULL, 0); + ret = ocfs2_divide_xattr_bucket(inode, handle, start_blk, + start_blk + blk_per_bucket, NULL, 0); le16_add_cpu(&first_xh->xh_num_buckets, 1); ocfs2_journal_dirty(handle, first_bh); @@ -4435,11 +4509,21 @@ out: return ret; } -/* check whether the xattr bucket is filled up with the same hash value. */ +/* + * check whether the xattr bucket is filled up with the same hash value. + * If we want to insert the xattr with the same hash, return -ENOSPC. + * If we want to insert a xattr with different hash value, go ahead + * and ocfs2_divide_xattr_bucket will handle this. + */ static int ocfs2_check_xattr_bucket_collision(struct inode *inode, - struct ocfs2_xattr_bucket *bucket) + struct ocfs2_xattr_bucket *bucket, + const char *name) { struct ocfs2_xattr_header *xh = bucket->xh; + u32 name_hash = ocfs2_xattr_name_hash(inode, name, strlen(name)); + + if (name_hash != le32_to_cpu(xh->xh_entries[0].xe_name_hash)) + return 0; if (xh->xh_entries[le16_to_cpu(xh->xh_count) - 1].xe_name_hash == xh->xh_entries[0].xe_name_hash) { @@ -4562,7 +4646,9 @@ try_again: * one bucket's worth, so check it here whether we need to * add a new bucket for the insert. */ - ret = ocfs2_check_xattr_bucket_collision(inode, &xs->bucket); + ret = ocfs2_check_xattr_bucket_collision(inode, + &xs->bucket, + xi->name); if (ret) { mlog_errno(ret); goto out; |